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Snowdrops effect, how does it work? (Read 1995 times)
Hokey
Ex Member



Snowdrops effect, how does it work?
Dec 2nd, 2003, 9:26pm
 
To all you brainboxes out there, can someone please tell me how do they make a gif work, where snowdrops are falling down the pc screen? I think it's a really good effect.  Cheesy
Hokey. Smiley
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locktightT
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Re: Snowdrops effect, how does it work?
Reply #1 - Dec 2nd, 2003, 11:36pm
 
Hi m8
 
It's just a piece of code that uses an image and plots/rmoves the picture several times over the same page to give the illusion that snow is falling - our web,aster Steve had it snowing here last year if you remember? It looks something like the script below
 
T ;D
 
<script language="JavaScript1.2">
 
  var snowsrc="icons/snow.gif"
  var no = 10;
 
  var url="icons/snow.html"
 
  var ns4up = (document.layers) ? 1 : 0;
  var ie4up = (document.all) ? 1 : 0;
 
 
  var dx, xp, yp;
  var am, stx, sty;
  var i, doc_width = 800, doc_height = 600;
   
  if (ns4up) {
    doc_width = self.innerWidth;
    doc_height = self.innerHeight;
  } else if (ie4up) {
    doc_width = document.body.clientWidth;
    doc_height = document.body.clientHeight;
  }
 
 
  dx = new Array();
  xp = new Array();
  yp = new Array();
  am = new Array();
  stx = new Array();
  sty = new Array();
   
  for (i = 0; i < no; ++ i) {  
    dx[i] = 0;
    xp[i] = Math.random()*(doc_width-50);
    yp[i] = Math.random()*doc_height;
    am[i] = Math.random()*20;
    stx[i] = 0.02 + Math.random()/10;
    sty[i] = 0.7 + Math.random();
    if (ns4up) {
     if (i < no / 2 ) {
       document.write("<layer name=\"dot"+ i +"\" left=\"15\" top=\"15\" visibility=\"show\"><a href=\""+url+"\"><img src='"+snowsrc+"' border=\"0\"></a></layer>");
     } else {
       document.write("<layer name=\"dot"+ i +"\" left=\"15\" top=\"15\" visibility=\"show\"><img src='"+snowsrc+"' border=\"0\"></layer>");
     }
    } else if (ie4up) {
     if (i < no / 2 ) {
       document.write("<div id=\"dot"+ i +"\" style=\"POSITION: absolute; Z-INDEX: "+ i +"; VISIBILITY: visible; TOP: 15px; LEFT: 15px;\"><a href=\""+url+"\"><img src='"+snowsrc+"' border=\"0\"></a></div>");
     } else {
       document.write("<div id=\"dot"+ i +"\" style=\"POSITION: absolute; Z-INDEX: "+ i +"; VISIBILITY: visible; TOP: 15px; LEFT: 15px;\"><img src='"+snowsrc+"' border=\"0\"></div>");
     }
    }
  }
   
  function snowNS() {
    for (i = 0; i < no; ++ i) {
     yp[i] += sty[i];
     if (yp[i] > doc_height-50) {
       xp[i] = Math.random()*(doc_width-am[i]-30);
       yp[i] = 0;
       stx[i] = 0.02 + Math.random()/10;
       sty[i] = 0.7 + Math.random();
       doc_width = self.innerWidth;
       doc_height = self.innerHeight;
     }
     dx[i] += stx[i];
     document.layers["dot"+i].top = yp[i];
     document.layers["dot"+i].left = xp[i] + am[i]*Math.sin(dx[i]);
    }
    setTimeout("snowNS()", 10);
  }
 
 
  function snowIE() {
    for (i = 0; i < no; ++ i) {  
     yp[i] += sty[i];
     if (yp[i] > doc_height-50) {
       xp[i] = Math.random()*(doc_width-am[i]-30);
       yp[i] = 0;
       stx[i] = 0.02 + Math.random()/10;
       sty[i] = 0.7 + Math.random();
       doc_width = document.body.clientWidth;
       doc_height = document.body.clientHeight;
     }
     dx[i] += stx[i];
     document.all["dot"+i].style.pixelTop = yp[i];
     document.all["dot"+i].style.pixelLeft = xp[i] + am[i]*Math.sin(dx[i]);
    }
    setTimeout("snowIE()", 10);
  }
 
 
  if (ns4up) {
    snowNS();
  } else if (ie4up) {
    snowIE();
  }
 
</script>  
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Hokey
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Re: Snowdrops effect, how does it work?
Reply #2 - Dec 3rd, 2003, 12:34pm
 
Thanks!!!!!!! Grin Grin Grin Grin Grin
I LOVE THE CHRISTMAS LIGHTS!!!!!!! Grin Grin Grin Grin
Hokey. Wink
PS, Thanks again. Grin
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